116 lines
1.5 KiB
Python
116 lines
1.5 KiB
Python
import logging
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import re
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from language.rules import default_rules
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from language.types import Language
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logger = logging.getLogger()
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permitted_starting_clusters = [
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"bh",
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"bl",
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"br",
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"bw",
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"by",
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"ch",
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"cl",
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"cr",
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"cw",
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"cy",
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"dh",
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"dj",
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"dr",
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"dw",
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"dy",
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"fl",
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"fn",
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"fr",
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"fw",
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"fy",
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"gh",
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"gl",
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"gn",
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"gr",
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"gw",
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"gy",
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"hy",
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"jh",
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"jy",
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"kh",
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"kl",
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"kr",
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"kw",
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"ky",
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"ll",
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"ly",
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"mw",
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"my",
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"ny",
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"ph",
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"pl",
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"pn",
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"pr",
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"pw",
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"py",
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"rh",
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"ry",
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"sb",
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"sc",
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"sd",
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"sf",
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"sg",
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"sh",
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"sj",
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"sk",
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"sl",
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"sm",
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"sn",
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"sp",
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"sr",
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"st",
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"sv",
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"sw",
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"sy",
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"th",
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"tr",
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"tw",
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"ty",
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"vy",
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"wh",
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"wr",
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"wy",
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"xh",
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"xy",
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"yh",
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"zb",
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"zc",
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"zd",
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"zh",
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"zl",
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"zm",
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"zn",
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"zr",
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"zw",
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"zy",
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]
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def cannot_start_with_two_consonants(language: Language, word: str) -> bool:
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found = re.compile(r"(^[bcdfghjklmnpqrstvwxz]{2})").search(word)
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if not found:
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return True
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first, second = found.group(1)
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if first == second:
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logger.debug(f"{word} starts with a repeated consonant.")
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return False
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return found in permitted_starting_clusters
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rules = default_rules.union(
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{
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cannot_start_with_two_consonants,
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}
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)
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